A 190-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.700 rev/s in 2.00 s? (State the magnitude of the force.)

Question

bobpursley · Answer

torque=force*radius=I*alpha force=(momentinertiadisk)alpha/radius alpha=.700*2PI/2 solve for force.

Anonymous · Answer

1.1