normal force down = 18.4*9.8 - 126 sin 34.1
so
friction force = .123 (18.4*9.8-126 sin 34.1)
work done by friction - friction force * 20 meters
A 18.4 kg block is dragged over a rough, horizontal
surface by a constant force of 126 N
acting at an angle of 34.1
◦
above the horizontal.
The block is displaced 20 m, and the
coefficient of kinetic friction is 0.123.
The acceleration of gravity is 9.8 m/s
2
.Find the work done by the force of friction.
Answer in units of J.
1 answer
2 answers