Change 18.3 g Al to mols. mols = grams/atomic mass. Then heat lost by Al + heat gained by water = 0
[mols Al x specific heat Al x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Solve for mass H2O after substitution.
A 18.3 g piece of aluminum (which has a molar heat capacity of 24.03 J/oC mol) is heated to
82.4oC and dropped into a calorimeter containing water (specific heat capacity of water is
4.18 J/goC) initially at 22.3oC. The final temperature of the water is 24.9oC. Calculate the
mass of water in the calorimeter. Ignore significant figures for this problem.
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