Uk = (friction force)/(normal force)
at constant velocity
The friction force is the horizontal component of the twowing force.
Uk = (82 cos30)/(Mg - 82 sin 30)
= 71.1/(176.4 - 41.0) = 0.525
a 18.0kg sled being pulled across horizontal surface at constant velocity. pulling force has magnitude of 82.0N and is directed at angle of 30 degree above horizontal. determine coefficient of kinetic friction
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