A 17- foot ladder is leaning against a wall, and begins to slide. The top of the ladder is falling at a rate of 2 feet per second at the instant that the bottom of the ladder is 8 feet from the wall. What is the rate of change of the distance between the bottom of the ladder and the bottom of the wall at this instant?

Also what is the rate of change of the area of the triangle made by the ladder?

1 answer

let h be the height along the wall, f the distance along the floor.
17^2=h^2+f^2
0=2h dh/dt + 2f df/dt
find df/dt, all else is given.note that dh/dt is negative, it is goind down.

area? Area=1/2 b*h=1/2 f*h
dA/dt=1/2 h df/dt + 1/2 f dh/dt
again, dh/dt is negative.