A 17.9 kg block is dragged over a rough, hor- izontal surface by a constant force of 74.1 N acting at an angle of angle 32.3◦ above the horizontal. The block is displaced 72.4 m and the coefficient of kinetic friction is 0.242. Find the work done by the 74.1 N force. The acceleration is 9.8 m/s^2. Ansewer in units of J.

asked by Kaylee

10 years ago

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1 answer

Work = Fap*cosA * d=74.1*cos32.3 * 72.4
= 4535 J.

answered by Henry

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Question

A 17.9 kg block is dragged over a rough, hor- izontal surface by a constant force of 74.1 N acting at an angle of angle 32.3◦ above the horizontal. The block is displaced 72.4 m and the coefficient of kinetic friction is 0.242. Find the work done by the 74.1 N force. The acceleration is 9.8 m/s^2. Ansewer in units of J.

1 answer

Work = Fap*cosA * d=74.1*cos32.3 * 72.4
= 4535 J.

Ask a New Question or answer this question.

Henry · Accepted Answer

Work = Fap*cosA * d=74.1*cos32.3 * 72.4 = 4535 J.