A 160.8mL sample of NaCl(aq) is reacted in 44.5mL of 1.23mol/L KMnO4(aq). What is the concentration of NaCl?

Answer 1

To find the concentration of NaCl, we need to use the equation:

M1V1 = M2V2

Where:
- M1 is the concentration of NaCl
- V1 is the volume of NaCl
- M2 is the concentration of KMnO4
- V2 is the volume of KMnO4

Plugging in the given values:

M1(160.8mL) = (1.23mol/L)(44.5mL)

Divide both sides by 160.8mL:

M1 = (1.23mol/L)(44.5mL) / 160.8mL

M1 ≈ 0.3391 mol/L

Therefore, the concentration of NaCl is approximately 0.3391 mol/L.