1/2(1500k)(30)^2 --> 2 <---/8
Where did that extra 2 come from?
I get 84,375 Watts
Yes, of course we are assuming that the full power of the engine is exerted all during the acceleration which is not practical with real engines and transmissions and tires.
a 1500kg sports car accelerates from 0 to 30 m/s in 8 seconds. Whaat is the power of its engine? Please help
power= work/time= 1/2 m v^2/8
1/2(1500k)(30)^2 2/8
=168750
is this correct?
1 answer