This is just like your last problem but reversed.
initial Ke = (1/2) m v^2 = (1/2)(1500) (225) Joules
that is the work done by the brakes (negative)
Final Ke - initial Ke = work in
Final is 0, initial is above ( 750)(225) so 0 - 168750 Joules
Force of brakes * 10 meters = work done by brakes (which is negative of course, force opposite to motion)
A 1500-kg wooden roller coaster car traveling at 15 m/s approaches the loading station where the under-track brake strips are pneumatically actuated to slow the car to a stop in 10m. What is the work done on the car by the brakes? What is the retarding force (friction) the car experiences?
if anyone could help that would be great!
1 answer
1 answer