a 15-kilogram box is dragged up an incline that is 8.0 meters long and makes an angle of 15 degrees with the horizontal. If the coefficient of friction between the box and the incline is .40, calculate the amount of work done by the applied force.

Answer 1

It is rather easy:
work= PE change+friction work
= mg8sin15 + 8*mg*CosTheta*.4

check that.

Answer 2

worked thanks...