To calculate the heat absorbed by the brass block, you can use the formula:
\[ Q = mc\Delta T \]
where:
- \( Q \) is the heat absorbed (in joules),
- \( m \) is the mass of the brass block (in kg),
- \( c \) is the specific heat capacity (in J/kg·K),
- \( \Delta T \) is the change in temperature (in K).
Given:
- \( m = 15 \) kg
- \( c = 376 \) J/kg·K
- Initial temperature \( T_i = 295 \) K
- Final temperature \( T_f = 350 \) K
First, calculate the change in temperature (\( \Delta T \)):
\[ \Delta T = T_f - T_i = 350 , \text{K} - 295 , \text{K} = 55 , \text{K} \]
Now, plug in the values to find \( Q \):
\[ Q = mc\Delta T = (15 , \text{kg}) \times (376 , \text{J/kg·K}) \times (55 , \text{K}) \]
Calculating this gives:
\[ Q = 15 \times 376 \times 55 \]
First calculate \( 15 \times 376 \):
\[ 15 \times 376 = 5640 , \text{J/K} \]
Now, multiply that by \( 55 \):
\[ Q = 5640 , \text{J/K} \times 55 , \text{K} = 310200 , \text{J} \]
Therefore, the total amount of heat absorbed by the brass is:
\[ \boxed{310200 , \text{J}} \]