A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast, in ft/sec, is the bottom of the ladder sliding away from the wall, at the instant when the bottom of the ladder is 9 ft from the wall? Answer with 2 decimal places. Type your answer in the space below. If your answer is a number less than 1, place a leading "0" before the decimal point (ex: 0.35).

asked by emma

9 years ago

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1 answer

x^2+y^2 = 225
so,
x dx/dt + y dy/dt = 0

Now plug in your numbers and solve for dx/dt

answered by Steve

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Question

A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast, in ft/sec, is the bottom of the ladder sliding away from the wall, at the instant when the bottom of the ladder is 9 ft from the wall? Answer with 2 decimal places. Type your answer in the space below. If your answer is a number less than 1, place a leading "0" before the decimal point (ex: 0.35).

1 answer

x^2+y^2 = 225
so,
x dx/dt + y dy/dt = 0

Now plug in your numbers and solve for dx/dt

Steve · Answer

x^2+y^2 = 225 so, x dx/dt + y dy/dt = 0 Now plug in your numbers and solve for dx/dt