To find the work done by the 167 N force, we need to find the component of the force in the direction of displacement. The component of the force in the direction of displacement is given by:
F_parallel = F * cos(angle)
Where F is the magnitude of the force (167 N) and angle is the angle above the horizontal (27.8°).
F_parallel = 167 N * cos(27.8°)
F_parallel = 149.57 N
The work done by the force is given by:
Work = F_parallel * displacement
Work = 149.57 N * 59 m
Work = 8816.63 J
Therefore, the work done by the 167 N force is 8816.63 J.
A 15.5 kg block is dragged over a rough,
horizontal surface by a constant force of 167 N
acting at an angle of 27.8° above the horizon-
tal. The block is displaced 59 m, and the
coefficient of kinetic friction is 0.232.
Previous R
15.5 kg
0 232
SARARIA
Find the work done by the 167 N force. The
acceleration of gravity is 9.8 m/s?
.
Answer in units of J. Answer in units of J.
1 answer