work done = change in kinetic energy
= (1/2) (15)(11.5^2 - 7.5^2)
A 15.0-kilogram mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the
total work that must be done on the mass to increase its speed to 11.5 meters per second?
3 answers
1140
570J is the correct answer
6 answers