A 15.0 kg stone slides down a snow-covered hill (the figure (Figure 1)), leaving point A with a speed of 10.0 m/s . There is no friction on the hill between points A and B, but there is friction on the level ground at the bottom of the hill, between B and the wall. After entering the rough horizontal region, the stone travels 100 m and then runs into a very long, light spring with force constant 2.20 N/m . The coefficients of kinetic and static friction between the stone and the horizontal ground are 0.20 and 0.80, respectively.

Answer 1

energy balance is zero.
initial KE at bottom=rough energy lost + spring energy absorbed
1/2 m *10^2=m*.2*g*100m + 1/2 2.2*x^2
where x is the distance the spring is copressed