A 14.9g of lead at 92.5C is dropped into a calorimeter with 165g of water at 20.0C. The final temperature of the system is 20.2C. What is the lead's specific heat?

Question

-Could I get help setting this up? I'm not sure how I'm supposed to set it up.

Answer 1

heat lost by Pb + heat gained by water = 0

[mass Pb x specific heat Pb x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
The only unknown is sp. h. Pb.