Fc = m*g = 14.7kg * 9.81N/kg = 144.1 N.=
Force of crate.
d = 7.2*sin11 = 1.37 m., Vertical.
Work = Fc * d = 144.1 * 1.37=198 Joules.
A 14.7 kg crate is pulled up a rough incline
with an initial speed of 1.5 m/s. The pulling
force is 124.0 N parallel to the incline, which
makes an angle of 11.0
◦
with the horizontal.
The coefficient of kinetic friction is 0.31 and
the crate is pulled a distance of 7.2 m.
The acceleration of gravity is 9.81 m/s
2
.
a) Find the work done by Earth’s gravity
on the crate.
Answer in units of J
1 answer
1 answer