M*g = 14.4 * 9.8 = 141.1 N.=Wt. of sled.
Fn = 141.1 - 66.9*sin32 = 105.7 N. =
Normal force.
Fap*Cos A-Fk = M*a.
66.9*Cos32-Fk = M*0 = 0.
Fk = 56.7 N. = Force of kinetic friction.
u = Fk/Fn.
A 14.4-kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 66.9 N and is directed at an angle of 32 ° above the horizontal. Determine the coefficient of kinetic friction
1 answer