momentum before = momentum after
momentum before = .013 * 330
momentum after = .013 * 270 + 2 v
so
2 v = .013 (330 - 270)
A 13g bullet traveling 330 m/s penetrates a 2.0 kg Block of wood and emerges going 270 m/s . If the block is stationary on a frictionless surface when hit how fast does it move after the bullet emerges?
4 answers
thank you
590.15
it was a gi Jane joke