A 13g bullet traveling 330 m/s penetrates a 2.0 kg Block of wood and emerges going 270 m/s . If the block is stationary on a frictionless surface when hit how fast does it move after the bullet emerges?

Answer 1

momentum before = momentum after

momentum before = .013 * 330

momentum after = .013 * 270 + 2 v

so

2 v = .013 (330 - 270)

Answer 2

thank you

Answer 3

590.15

Answer 4

it was a gi Jane joke