Asked by lori
A 135 g sample of ice is in a freezer at -21 ˚C. It is removed from the freezer and allowed to melt and the resulting water warms up to the room temperature, 23˚C. How much energy is absorbed by the 135g sample? The specific heat capacity of ice is 2.0 J/g˚C, the specific heat capacity of water is 4.184 J/g˚C and the heat of fusion of ice is 0.33 kJ/g
Answers
Answered by
DrBob222
q1 = mass ice x (Tfinal - Tinitial) = ?
q2= mass ice x heat fusion = ?
q3 = mass water x specific heat H2O x (Tfinal-Tinitial) = ?
Total = q1 + q2 + q3
Post your work if you get stuck.
q2= mass ice x heat fusion = ?
q3 = mass water x specific heat H2O x (Tfinal-Tinitial) = ?
Total = q1 + q2 + q3
Post your work if you get stuck.
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