A 13.8 g piece of Zn metal was heated to 98.6 oC and then dropped in 45.6 g of water at 25.0 oC. Assuming that no heat is lost to the surroundings, determine the specific heat capacity of Zn if the final temperature of the water was 27.1 oC C=6461.39

Question

A 13.8 g piece of Zn metal was heated to 98.6 oC and then dropped in 45.6 g of water at 25.0 oC.  Assuming that no heat is lost to the surroundings, determine the specific heat capacity of Zn if the final temperature of the water was 27.1 oC C=6461.39

DrBob222 · Answer

heat lost by Zn + heat gained by water = 0 [mass Zn x specific heat Zn x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0 Substitute and solve for the one unknown.