A 12N force is applied to a 20kg door If a frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.

Answer 1

torque= I*angacc

12*.8=1/3 m (.8^2)*angacceleration

Answer 2

A 12N force is applied to a 20kg door If a 5m.N frictional torque is present what will be the angular acceleration of the door The door is 80cm wide and I=1/3ml^2.

Answer 3

you are correct, I did not subtract frictional torque.

12*.8-.5= .....