A 1277 mL sample of nitrogen (N2) was collected by displacement of water at 24 degrees C under a total barometric pressure of 966 torr. What mass of dry nitrogen was collected? The vapor pressure of water at 24 degrees C is 22 torr.

Answer in units of g

3 answers

Use PV = nRT and calculate n.
P in torr wet H2 = 966 torr
P H2O torr = 22 torr
PH2 dry = 966-22 = ?
PH2 in atm = ?/760

V = 1.277 L
n = unknown--Solve for this.
R = 0.08206 L*atm/mol*K
T = 297K

Find n, then n = grams/molar mass. You know n and molar mass, solve for grams.
1.59g
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