A 125 kg crate rests on the flatbed of a truck that moves at a speed of 15.0 m/s around an unbanked curve whose radius is 66.0m. This crate does not slip relative to the truck. Obtain the magnitude of the static frictional force that the truck bed exerts on the crate.

Question

A 125 kg crate rests on the flatbed of a truck that moves at a speed of 15.0 m/s around an unbanked curve whose radius is 66.0m. This crate does not slip relative to the truck. Obtain the magnitude of the static frictional force that the truck bed exerts on the crate.
If you could explain/show how you got the answer to this, it would be great!
Thanks

Anonymous · Answer

The frictional force is compensating for the inward force to due to circular motion, for which you use the formula F=(mv^2)/r F=((125)(12^2))/66=273N pretty sure that's correct

Lynda · Answer

Thanks! That helped a lot

Andys · Answer

The pipe has mass of 500kg and rests on the flat bed of the truck. The static and dynamic coefficients of friction between the pipe and the truck bed are respectively μχ=0,04 andμκ=0,35 the truck starts from rest with a constant acceleration of