how long does it take to stop, with acceleration a?
22.5t + 1/2 at^2 = 41
Now, with that t,
22.5 + at = 0
That gives you the value of a.
F = ma
a 1240 kg automobile stops in a distance of 41m. if initial velocity was 22.5m/s, what force did the road exert on the car to stop it? Answer pls... Thank You
2 answers
How to get acceleration? and time?
1 answer