A 121 cm-long, 3 g string oscillates in its m = 3 mode with a frequency of 154 Hz and a maximum amplitude of 5.0 mm. What are the wavelength and the tension in the string?

Answer 1

1.21 m long so wavelength = 2L/3 = .807m
.003 kg/1.21 m = .00248 kg/m
v = sqrt(Tension/kg/m) =sqrt(T/.00248)
f = n v/(2L)
154 = 3 v/(2.42)
v = 124.2m/s
124.2 = sqrt(T/.00248)
T/.00248 = 15425
T = 38.3 Newtons

The amplitude has nothing to do with it.

Answer 2

Thank you so very much Damon!