A 1200 kg car is traveling at 45 km/h and hits a 1000 kg car parked on the edge of a 70 m deep canyon. What is the velocity of the two car wreck?

Answer 1

momentum is conserved.

M1*V1+0=(M1+M2)V solve for V I would change km/h to m/s

Answer 2

M1*V1 + 0 = (m1+m2)V
1200V1+0=(1200+1000)45
1200V1 = 2200*45
1200V1 = 99000
V1 = 99000/1200
V1 = 82.5km/h