KEenergy car-friction*distance=remaining energy.
1/2 m v^2-6000*distance=0
solve for distance.
a 1200 kg car going 30 m/s applies its brakes and skids to rest. if the friction force between the sliding ires and the pavement is 6000 N, how far does the car skid before coming to rest. I know the ans is 90 m
what work/energy formula should i use to get this answer? can you help me plug in the numbers where they belong?
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