(b) Output power = 3.20 hp = 2387 Watts
Input power = 2387/0.81 = 2947 W
Electrical energy delivered in 3.60 h
= 2947 J/s*3.2 h*3600 s/h = 3.395*10^7 J
(c) 2.947 kW*3.2 h = ___ kWh
Multiply that by the cost per kWh
A 120-V motor has mechanical power output of 3.20 hp. It is 81.0% efficient in converting power that it takes in by electrical transmission into mechanical power.
(a) Find the current in the motor.
Answer: 24.6A
(b) Find the energy delivered to the motor by electrical transmission in 3.60 h of operation.
?J
(c) If the electric company charges $0.160/kWh, what does it cost to run the motor for 3.60 h?
$
1 answer