a .w =588.6 N
b.v=√1177.2÷√12 metre per second
A 12 kg block is released from rest on a 30 degree fricitonless incline. Below the block is a spring that can be compressed 2 cm by a force of 270 N. The block momentarily srops when it compresses the spring by 5.5 cm.
a) How far does the block move down the incline from its rest position to this stopping point?
b) What is the speed of the block just as it touches the spring?
a) Would I solve for k in 1/2kx^2
b)K.E.= 1/2mv^2 I would solve for v?
a) on the incline, the component of weight down the slope is mg*sinTheta. That is the force on the spring.
b. The energy found by spring compression will equal 1/2 mv^2. Solve for v.
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