A 12 ft by 15 ft rectangular swimming pool has a 4 ft wide no slip surface around it. What is the outer perimeter of the no slip surface?

Answer 1

The length of the swimming pool including the no slip surface around it is 12 ft + 2 * 4 ft = 12 ft + 8 ft = <<12+2*4=20>>20 ft.
The width of the swimming pool including the no slip surface around it is 15 ft + 2 * 4 ft = 15 ft + 8 ft = <<15+2*4=23>>23 ft.
The outer perimeter of the no slip surface is 2 * (20 ft + 23 ft) = 2 * 43 ft = <<2*(20+23)=86>>86 ft. Answer: \boxed{86}.

Answer 2

What is the circumference of the circle below in terms of π
2.8

Answer 3

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle.

In this case, we don't have the radius of the circle, but we have the diameter, which is twice the radius. So we can start by finding the radius by dividing the diameter by two:

r = diameter / 2 = 2.8 / 2 = 1.4

Now we can use the formula for the circumference:

C = 2πr = 2π(1.4) = 2 * 1.4 * π = 2.8π

Therefore, the circumference of the circle is 2.8π.

Answer 4

What is the perimeter of △PQR
with vertices P(-9,2), Q(-7,3) and R(3,2) . Round your answer to the nearest tenth.

Answer 5

To find the perimeter of triangle PQR, we need to calculate the distance between each pair of vertices and then sum them.

The distance formula between two points (x₁, y₁) and (x₂, y₂) is given by:
d = √((x₂ - x₁)² + (y₂ - y₁)²)

So, let's calculate the distances between the vertices:

Distance PQ:
d₁ = √((-7 - (-9))² + (3 - 2)²)
= √(2² + 1²)
= √(4 + 1)
= √5

Distance QR:
d₂ = √((3 - (-7))² + (2 - 3)²)
= √(10² + (-1)²)
= √(100 + 1)
= √101

Distance RP:
d₃ = √((-9 - 3)² + (2 - 2)²)
= √((-12)² + 0²)
= √(144 + 0)
= √144
= 12

Now, let's sum the distances to find the perimeter:
P = √5 + √101 + 12 ≈ 24.2

Therefore, the perimeter of triangle PQR, rounded to the nearest tenth, is approximately 24.2.

Answer 6

You are tiling a kitchen floor that is 13 ft. wide by 4 yd. long. How many square yards of tile do you need?