A 12.0 kg object is on a surface that is inclined 30 degrees and the coefficient of friction is 0.65.

Determine the force of static friction if the block remains stationary.

1 answer

Fo = M*g = 12 * 9.8 = 117.6 N. = Force of the object.

Fp = 117.6*sln30 = 58.8 N. =
Force parallel to the incline.

Fn = 117.6*Cos30 = 101.8 N. = Normal force.

Fs = u*Fn = 0.65 * 101.8 = 66.2 N. - Force of static friction.