q absorbed by water = mass x specific heat x (Tfinal-Tintial)
q lost by metal = heat absorbed by water
[mass metal x specific heat metal x (Tfinal-Tintial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for sp. h. metal.
A 11.6 g sample of an unknown metal was heated to 100.0 oC and then added to 25.0 g of water at 23.0 degrees Celsius in an insulated calorimeter. At thermal equilibrium, the temperature of the water in the calorimeter was 24.8 degrees Celsius.
What is the heat absorbed or lost by the water? In joules
How much heat is absorbed or lost by the metal? In joules
What's the specific heat of metal? (Joules/ grams x degrees Celsius )
1 answer
1 answer