A 10uf capacitor is charged by an 80v supply and then connected across an uncharged 20uf capacitor calculate the final p.d across each capacitor and final charge on each

Answer 1

I guess pd means potential difference (voltage) ?
original
C = Q/V
10*10^-6 = Q / 80
Q = 800 *10^-6
final
total C = 30 *10^-6 and total charge = 800*10^-6
V = Q/C = 800*10^-6 / 30*10^-6 = 80/3 = 26.7 volts
Q1 = 26.7 * 10*10^-6
Q2 = 26.7 * 20*10^-6

Answer 2

I am learning