A 10kg box is pulled a distance of 100m along a level floor at constant velocity using a force of 40 N at an angle of 35 degrees above the horizontal. If the box is pulled at constant velocity, what is the coefficient of friction between the bottom of the box and the floor?

Answer 1

Force horizontal=40cos35
That will equal friction

Force normal=mg-40cos35

friction=forcehorizontal
mu(mg-40sin35)=40Cos35
solvefor mu