weight = 103 (big guy!) * 9.81 = 1010 N
F = .729 * 1010 = 737 N
F = m a
-737 = 103 a
(negative because stopping)
a = - 7.15
v = Vi + a t
0 = Vi -7.15 (1.27)
Vi = 9.08 m/s
A 103-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is ìk = 0.729. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.27 s, what is his initial speed?
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