A 100N weight is suspended by three strings A,B,C as shown below what is the cension in each of the strings

Answer 1

In order to find the tension in each of the strings, we must first resolve the weight (100N) into its components along the x-axis and y-axis.

Let's assume that angle between string A and the vertical is θ, then the tension in each of the strings can be calculated as follows:

Tension in string A (TA) = Tcosθ
Tension in string B (TB) = Tsinθ
Tension in string C (TC) = T

Where T is the total tension in all the strings.

Since the weight is in equilibrium, the sum of the forces in the vertical direction should be equal to zero:

TA + TB - 100N = 0
Tcosθ + Tsinθ - 100N = 0
T(cosθ + sinθ) = 100N
T = 100N / (cosθ + sinθ)

Now, we can find the tension in each of the strings:

TA = Tcosθ = (100N / (cosθ + sinθ)) * cosθ
TB = Tsinθ = (100N / (cosθ + sinθ)) * sinθ
TC = T = 100N / (cosθ + sinθ)

These equations give us the tensions in each string as a function of the angle θ.