A 1000kg elevator carries a maximum load of 800kg. A constant frictional force of 5000N s the elevator's motion upward. What minimum power, in kilowatts, must the motor deliver to lift the fully loaded elevator at a constant speed of 3m/s?
2 answers
(Max. Weight + Friction)* (velocity) = Power
suppose the same elevator with the same load decends at 3.00 m/s. what minimum power is required?(Here, the motor removes energy from the elevator by not allowing it to fall freely
5 answers