A 10000 N car comes to a bridge during a storm and finds the bridge washed out. The 750 N driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 21.6 m above the river, while the opposite side is a mere 3.60 m above the river. The river itself is a raging torrent 63.0 m wide.
How fast should the car be traveling just as it leaves the cliff in order to clear the river and land safely on the opposite side?
got it....33 m/s
What is the speed of the car just before it lands safely on the other side?
yeah...don't know...not even a little bit
What is the speed of the car? The easy way is to use Energy..
He started with 1/2 m v^2 (and you figured v) plus mgh of Potential energy (h=21.6-3.6). Add those. Then when he landed, he had 1/2 m v^2 of energy, so calcuate v.
The other way is you know the initial horizontal velocity, that is also the final horizontal velocity. The vertical velocity at impact will be v= sqrt(2gh).Add those two velocities as vectors.
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