A 1000 kg car is initially at rest. If the motor does 10,000J of work on the car, what is the car’s final speed? (Neglect friction, and assume that the car is on level ground.)

Answer 1

Work = KE2-KE1 = KE2-0 = KE2.
KE2 = 0.5M*V^2 = 10,000 J.
500*V^2 = 10,000, V = ?.