A 100 kg sample of a metal is cooled from 100°C to 20°C by removing 20 kcal of heat. Calculate the specific heat capacity of the metal.

Answer 1

20kcal=100kg*c*80 C

c=20k/(100k*8O)=.2/80=.02/8
= .0025 cal/g-C

Answer 2

20 kcal =83736 J
Q=cmΔT

c=Q/mΔT