total energy is ... 1/2 m v^2 + m g h ... (1/2 * 100 * 10^2) + (100 * 9.8 * 30)
... 5 kJ + 29.4 kJ = 34.4 kJ
potential energy becomes kinetic energy
at ground height ... 1/2 * 100 * v^2 = 34.4 kJ ... v^2 = 688 m^2/s^2
A 100 kg roller coaster is moving at 10 m/s while travelling 30 m above the ground. How fast will it be travelling when it reaches ground height?
Can you do an explanation with it too please whoever answers it
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