Assuming the volumes are additive, the final concn of the HCl is
0.1 x (10/100) = 0.01 M so pH = = log(H^+). The H^+ contributed by the H2O is small enough to be ignored in this case.
A 10 ml of hydrochloric acid solution of concentration equal to 0.1 mol per litre is added 90 ml of pure water. What's the pH of the final solution?
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