A 10 kg block slides up a hill to a height of 5.8 m. If 414 J of thermal energy are generated, how fast was the block going at the bottom of the hill?

Answer 1

Initial kinetic energy = (1/2) M Vo^2
= (thermal energy generated) + (potential energy increase)
= 414 J + M g H = 982 J

Solve for Vo