A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

30h=10
30 h equals 10

1,280+30h=0
1,280 plus 30 h equals 0

1,280−30h=0
1,280 minus 30 h equals 0

10−30h=0
10 minus 30 h equals 0

Answer 1

To determine how long the water in the cooler will last, we can relate the total amount of water in ounces to the amount being consumed per hour.

1. The total amount of water in the cooler is 1,280 ounces (since 10 gallons = 1,280 ounces).
2. The amount of water consumed each hour is 30 ounces.

Let \( h \) represent the number of hours the water lasts. The water will run out when the total amount consumed equals the total water available. Therefore, we can set up the following equation:

\[ 1,280 - 30h = 0 \]

This equation states that if we start with 1,280 ounces and subtract 30 ounces for each hour \( h \), we will reach 0 ounces when the water runs out.

So, the correct equation is:

1,280 − 30h = 0

This indicates that the water in the cooler will last until the total water consumed equals the initial amount available.