A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces)(1 point)

Responses

30h = 10
30h = 10

1,280 - 30h = 0
1,280 - 30h = 0

1,280 + 30h = 0

1 answer

To determine how long the water in the cooler will last, we need to set up an equation based on the amount of water available and the rate at which it is being used.

We know that the cooler has a total of 1,280 ounces of water (since 10 gallons = 1,280 ounces) and that 30 ounces are being consumed each hour.

To find out how long (h) the water will last, we can set up the equation:

\[ 1,280 - 30h = 0 \]

This equation states that when you subtract the total amount of water consumed (30 ounces per hour times the number of hours, h) from the total amount of water (1,280 ounces), it will equal zero when the water runs out.

So, the correct response is:

1,280 - 30h = 0.