A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

30h=10
30 h equals 10

10−30h=0
10 minus 30 h equals 0

1,280+30h=0
1,280 plus 30 h equals 0

1,280−30h=0

Answer 1

To find out how long the water in the cooler will last, we need to write an equation that models the situation.

The total amount of water in the cooler is 1,280 ounces (since 10 gallons = 1,280 ounces). Each hour, 30 ounces of water is removed. If \( h \) represents the number of hours, then the amount of water remaining after \( h \) hours is:

\[ 1,280 - 30h \]

We want to find out when the cooler is empty, which means setting the remaining amount of water to 0:

\[ 1,280 - 30h = 0 \]

So the correct equation to show how long the water in the cooler will last is:

1,280 - 30h = 0

This means the correct response is "1,280−30h=0."