A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

1,280+30h=0
1,280 plus 30 h equals 0

30h=10
30 h equals 10

10−30h=0
10 minus 30 h equals 0

1,280−30h=0

Answer 1

To find how long the water in the cooler will last, let \( h \) represent the number of hours the water lasts. The initial amount of water in the cooler is 1,280 ounces, and every hour 30 ounces are consumed. The equation that represents this scenario is:

\[ 1,280 - 30h = 0 \]

So, the correct response is:

1,280 − 30h = 0.