A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point) Responses 1,280−30h=0 1,280 minus 30 h equals 0 1,280+30h=0 1,280 plus 30 h equals 0 10−30h=0 10 minus 30 h equals 0 30h=10 30 h equals 10

Answer 1

To find out how long the water in the cooler will last, we can set up an equation based on the amount of water being consumed over time.

1. Total amount of water: The cooler holds 10 gallons, which is equal to 1,280 ounces.
2. Water consumption rate: 30 ounces of water are consumed every hour.

Let \( h \) represent the number of hours the water lasts. The equation that represents the total amount of water consumed in ounces over time is:

\[ 1,280 - 30h = 0 \]

This equation states that when the total starts at 1,280 ounces and we subtract 30 ounces for each hour \( (30h) \), it becomes zero when the water runs out.

So, the correct equation showing how long the water in the cooler will last is:

\[ 1,280 - 30h = 0 \]