A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

10−30h=0
10 minus 30 h equals 0

30h=10
30 h equals 10

1,280−30h=0
1,280 minus 30 h equals 0

1,280+30h=0

Answer 1

To find out how long the water in the cooler will last, we need to set up an equation where the total amount of water in the cooler (1,280 ounces) is equal to the amount of water consumed over time.

Each hour, 30 ounces of water are consumed, so after \( h \) hours, the total amount of water consumed is \( 30h \).

Initially, there is 1,280 ounces of water in the cooler. As water is consumed, we want to find out when the total amount of water left will be zero:

\[ 1,280 - 30h = 0 \]

This equation shows the initial amount of water minus the amount consumed over time, and it equals zero when the cooler is empty.

So, the correct response is:

1,280 - 30h = 0